11x^2-96x-336=0

Solution for 11x^2-96x-336=0 equation:

11x^2-96x-336=0

a = 11; b = -96; c = -336;
Δ = b2-4ac
Δ = -962-4·11·(-336)
Δ = 24000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24000}=\sqrt{1600*15}=\sqrt{1600}*\sqrt{15}=40\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-40\sqrt{15}}{2*11}=\frac{96-40\sqrt{15}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+40\sqrt{15}}{2*11}=\frac{96+40\sqrt{15}}{22}
$